lesser than the stretching frequency of CO in Fe(CO)5.
greater than the stretching frequency of CO in Fe(CO)5.
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The Correct Option isA, D
Solution and Explanation
(A) The stretching frequency of CO in H3B·CO is greater than that in free CO due to
the electron-withdrawing effects of the boron in the H3B group, which increases the bond
strength and results in a higher stretching frequency.
(B) This statement is incorrect
because the stretching frequency of CO in H3B·CO is greater, not lesser.
(C) The
stretching frequency of CO in Fe(CO)5 is lower than that in H3B·CO because the iron center
donates electron density to the CO ligand, weakening the C–O bond and lowering the
frequency.
(D) The stretching frequency of CO in H3B·CO is greater than that in
Fe(CO)5 due to the different electronic effects of the metal center in Fe(CO)5, which leads to
weaker bonding with CO and thus a lower frequency.