Question:

The stress required to produce a fractional compression of 1.5% in a liquid having bulk modulus of \( 0.9 \times 10^9 \, {Nm}^{-2} \) is:

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To calculate the stress required for a given fractional compression, use the relation \( K = -\frac{{Stress}}{{Fractional compression}} \). Rearranging the equation will give you the stress.
Updated On: Mar 12, 2025
  • \( 2.48 \times 10^7 \, {Nm}^{-2} \)
  • \( 0.26 \times 10^7 \, {Nm}^{-2} \)
  • \( 3.72 \times 10^7 \, {Nm}^{-2} \)
  • \( 1.35 \times 10^7 \, {Nm}^{-2} \)
  • \( 4.56 \times 10^7 \, {Nm}^{-2} \)
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The Correct Option is D

Solution and Explanation

The bulk modulus \( K \) is related to stress (\( \sigma \)) and the fractional change in volume (\( \Delta V / V \)) by the equation: \[ K = -\frac{{Stress}}{{Fractional compression}}, \] where: - \( K = 0.9 \times 10^9 \, {Nm}^{-2} \) is the bulk modulus,
- The fractional compression is given as \( 1.5% = 0.015 \).
Rearranging the equation to solve for stress (\( \sigma \)): \[ {Stress} = - K \times {Fractional compression} = 0.9 \times 10^9 \times 0.015 = 1.35 \times 10^7 \, {Nm}^{-2}. \] Thus, the required stress is \( 1.35 \times 10^7 \, {Nm}^{-2} \), which corresponds to option (D).
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