Step 1: Analyze the reaction stoichiometry.
The reaction is:
\[
3\text{A} + \text{B} \rightarrow \text{C} + 2\text{D}.
\]
In a steady-state gas phase reaction on a catalyst surface, the fluxes of species are related by their stoichiometric coefficients. The flux \( N_i \) represents the molar flux of species \( i \) (moles per unit area per unit time) toward or away from the catalyst surface.
The stoichiometric coefficients are:
A: -3 (reactant, consumed),
B: -1 (reactant, consumed),
C: +1 (product, produced),
D: +2 (product, produced).
The negative sign indicates consumption, and the positive sign indicates production.
Step 2: Apply the stoichiometric relationship for fluxes.
For a reaction \( \sum \nu_i S_i = 0 \), where \( \nu_i \) is the stoichiometric coefficient (negative for reactants, positive for products), the fluxes are related by:
\[
\frac{N_i}{\nu_i} = \text{constant}.
\]
This means the molar fluxes are proportional to the stoichiometric coefficients. For species A and D:
\( \nu_A = -3 \),
\( \nu_D = +2 \).
Thus:
\[
\frac{N_A}{\nu_A} = \frac{N_D}{\nu_D},
\]
\[
\frac{N_A}{-3} = \frac{N_D}{2}.
\]
Solving for the flux ratio \( N_A / N_D \):
\[
N_A = \frac{-3}{2} N_D,
\]
\[
\frac{N_A}{N_D} = -\frac{3}{2} = -1.5.
\]
Step 3: Interpret the sign of the flux ratio.
\( N_A \) is negative because A is a reactant being consumed (flux toward the surface).
\( N_D \) is positive because D is a product being produced (flux away from the surface).
The negative sign in the ratio \( N_A / N_D = -1.5 \) reflects the opposite directions of the fluxes.
Step 4: Evaluate the options.
(1) -2: Incorrect, as the ratio is -1.5, not -2. Incorrect.
(2) -0.5: Incorrect, as the ratio is -1.5, not -0.5. Incorrect.
(3) -1.5: Correct, as derived from the stoichiometric relationship.
Correct.
(4) 2: Incorrect, as the ratio is negative due to the opposite directions of the fluxes. Incorrect.
Step 5: Select the correct answer.
The flux ratio \( N_A / N_D \) for the reaction is -1.5, matching option (3).