In steady state, the capacitor acts as an open circuit (infinite resistance). Therefore, the 5 $\Omega$ resistor is not part of the circuit. The circuit simplifies to:
The total resistance is 2 $\Omega$ + 3 $\Omega$ = 5 $\Omega$. Using Ohm's law, I = V/R = $\frac{10 \, V}{5 \, \Omega} = 2 \, A$
Determine the equivalent resistance of the parallel combination of the two resistors (X and Y).
Study the circuit shown in which two resistors X and Y of resistances 3 Ω and 6 Ωrespectively are joined in series with a battery of 2V.
Find the current drawn from the battery by the series combination of the two resistors (X and Y).
Study the circuit shown in which two resistors X and Y of resistances 3 Ω and 6 Ω respectively are joined in series with a battery of 2V.
In which combination of resistors will the (i) potential difference across X and Y and (ii) current through X and Y, be the same
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :