\(N_2O_4 ⇋ 2NO_2\)
\(t = 0\) \(1\) \(0\)
\(t = t_{eq.}\) \(1 – 0.5\) \(2×0.5\)
\(P_{N_2O_4} = 0.33\ atm\)
\(P_{NO_2} = 0.66\ atm\)
\(K_p = \frac {(P_{NO_2})^2}{P_{N_2O_4}}\)
\(= \frac {(0.66)^2}{0.33}\)
\(= 1.33\)
\(△G = -RT\ ln K_p\)
\(△G = -0.831 \times 300 \times 2.3 \times log\ 1.33\)
\(△G ≃ 710\ Jmol^{-1}\)
So, the correct answer is \(710\ Jmol^{-1}.\)
The portion of the line \( 4x + 5y = 20 \) in the first quadrant is trisected by the lines \( L_1 \) and \( L_2 \) passing through the origin. The tangent of an angle between the lines \( L_1 \) and \( L_2 \) is:
Halogens are the group 17 elements of the periodic table. The term ‘halogen’ means ‘salt-producing’, hence the name halogens as they possess the tendency to form salts after reacting to metals. It generally has five elements:
These are all naturally occurring halogens but Tennessine (Ts) is an artificially created halogen.
Halogens are highly reactive elements and are highly electronegative. They have a high tendency to react with metals to form salts. They are also known as Group 17 elements. They have 7 electrons in their outer shell with a configuration of (ns2 np5). Fluorine being the first halogen in group 17, is highly reactive. Astatine is a halogen because of its resemblance with iodine despite it being radioactive.
The general electronic configuration for group 17 elements is ns2np5. This configuration clearly shows that they have 7 electrons in their valence shell. They require one more electron to complete their octet and achieve noble gas configuration.