Step 1: Standard Enthalpy of Formation.
The standard enthalpy of formation of an element in its most stable form at 1 bar and a specified temperature is defined as zero. This means elements in their standard states have a standard enthalpy of formation of zero.
Step 2: Analyzing the options.
- (1) S (Monoclinic): Sulfur in its monoclinic form is its most stable allotrope at 1 bar, so its enthalpy of formation is zero.
- (2) P (White): White phosphorus is not its most stable allotrope at standard conditions, so its enthalpy of formation is nonzero.
- (3) Br\(_2\) (liquid): Bromine is a liquid at 1 bar and standard temperature, and it is its most stable form, so its enthalpy of formation is zero.
- (4) O\(_2\) (g): Oxygen gas is the most stable form of oxygen at standard conditions, and its enthalpy of formation is zero.
Final Answer: \[ \boxed{\text{(4) } O_2 \, (\text{g})} \]
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