The upward lift on a wing is given by Bernoulli's principle, which relates the difference in the velocities of air over the upper and lower surfaces of the wing to the lift force.
The pressure difference \( \Delta P \) between the upper and lower surfaces is related to the velocities \( v_1 \) and \( v_2 \) by: \[ \Delta P = \frac{1}{2} \rho (v_1^2 - v_2^2) \] The upward lift \( L \) is the force exerted by this pressure difference on the cross-sectional area of the wing. Therefore, the lift force is: \[ L = \Delta P \cdot A = \frac{1}{2} \rho A (v_1^2 - v_2^2) \]
Thus, the correct answer is: \[ \text{(3) } \frac{1}{2} \rho A (v_1^2 - v_2^2) \]
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure.
The angular velocity of the system after the particle sticks to it will be: