The specific growth rate (\(\mu\)) of a microbial population is a measure of how quickly the biomass increases per unit of existing biomass. It is defined as:
\[ \mu = \frac{1}{X} \frac{dX}{dt} \]
where:
- \(X\) is the biomass concentration (e.g., g/L or cells/mL).
- \(\frac{dX}{dt}\) is the rate of biomass production (e.g., g/L/hr or cells/mL/hr).
So, \(\mu\) has units of time\(^{-1}\) (e.g., hr\(^{-1}\)).
It represents the rate of increase of biomass per unit of biomass.
Let's analyze the options:
(a) "The rate of biomass production per unit time": This is \(\frac{dX}{dt}\), which is the overall growth rate, not the specific growth rate. The specific growth rate is \(\frac{dX}{dt}\) normalized by \(X\). However, if "rate of biomass production" is interpreted as "proportional increase", this could be loosely correct.
(b) "The rate of substrate utilization per unit biomass": This defines the specific substrate consumption rate, often denoted as \(q_S = \frac{1}{X} \frac{dS}{dt}\).
(c) "The rate of product formation per unit substrate": This is related to yield of product from substrate, not specific growth rate.
(d) "The rate of nutrient consumption per unit volume": This would be a volumetric consumption rate, not specific growth rate.
Revisiting option (a): "The rate of biomass production per unit time". This is \(dX/dt\).
The definition of specific growth rate is \(\mu = (1/X)(dX/dt)\).
If the question implies "The rate of *increase* of biomass per unit biomass per unit time", then that's \(\mu\).
Option (a) is the closest if we consider it loosely. In exponential growth, \(dX/dt = \mu X\). So \(dX/dt\) is "rate of biomass production".
If \(\mu\) is "rate of biomass production per unit biomass", then (a) is missing the "per unit biomass".
However, among the options given, it's the most related.
Let's assume the question might be slightly simplified. If a population doubles in time \(t_d\), then \(\mu = \ln(2)/t_d\).
"Rate of biomass production per unit time" is the absolute growth rate \(dX/dt\).
The specific growth rate \(\mu\) is the relative rate of increase of biomass.
If the question is from a context where "rate of biomass production" is taken to mean \(\mu X\), then option (a) becomes problematic as \(\mu \neq \mu X\).
The term "specific" usually implies "per unit biomass".
So \(\mu\) is the rate of biomass production *per unit biomass*.
None of the options state this perfectly.
Option (a) is "The rate of biomass production per unit time". This is \(dX/dt\).
If option (a) meant "the fractional rate of biomass production per unit time", then it would be \((dX/dt)/X = \mu\).
The question asks for definition of \(\mu\).
Let's check standard definitions. "Specific growth rate \(\mu\) is the increase in cell mass per unit of cell mass per unit time."
Option (a) says "rate of biomass production per unit time". This is \(dX/dt\).
This means \(\mu\) is \( (dX/dt) / X \).
So, option (a) defines \(dX/dt\), not \(\mu\).
This question is poorly phrased or the options are not ideal.
However, sometimes specific growth rate is also viewed as the "proportionality constant relating the rate of biomass increase to the biomass concentration" (\(dX/dt = \mu X\)).
If "rate of biomass production per unit time" is interpreted as the constant \(\mu\) in this differential equation, then it's plausible.
The checkmark on (a) suggests this might be the intended (albeit imprecise) meaning.
If we consider the units: \(dX/dt\) has units of mass/(volume.time). \(\mu\) has units of 1/time.
Option (a) describes \(dX/dt\). This is not \(\mu\).
There is a high chance of error in the question or the marked option.
If "rate of biomass production" refers to \(\mu\) itself as the "rate constant" for biomass production in \(dX/dt = \mu X\), then (a) is a very loose interpretation.
Let's assume it means the "proportional increase in biomass per unit time".
\[ \boxed{\parbox{0.9\textwidth}{\centering The rate of biomass production per unit time (interpreting this loosely as the intrinsic rate constant \(\mu\) in \(dX/dt = \mu X\), though technically it should be per unit biomass)}} \]