To solve the problem, we analyze the fluorination reaction of phosphorus pentachloride (PCl5) in a polar organic solvent.
Fluorination of PCl5:
When PCl5 reacts with fluorine or a fluorinating agent in polar organic solvents, it often forms ionic species due to ligand exchange and formation of complex ions.
Known species formed:
- The cation [PCl4]+ (tetrachlorophosphonium ion)
- The anion [PF6]- (hexafluorophosphate ion)
These ions result from partial substitution of chlorine by fluorine in PCl5 and subsequent complex formation.
Therefore, the species formed are:
\[
[PCl_4]^+ [PF_6]^-
\]
Final Answer:
\[
\boxed{\text{[PCl}_4]^+ \text{[PF}_6]^-\ \text{and not the other species}}
\]
which corresponds to the second option:
[PCl4]+[PCl4F2]- and [PCl4]+[PF6]-
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are : 
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is : 

Let $ P(x_1, y_1) $ and $ Q(x_2, y_2) $ be two distinct points on the ellipse $$ \frac{x^2}{9} + \frac{y^2}{4} = 1 $$ such that $ y_1 > 0 $, and $ y_2 > 0 $. Let $ C $ denote the circle $ x^2 + y^2 = 9 $, and $ M $ be the point $ (3, 0) $. Suppose the line $ x = x_1 $ intersects $ C $ at $ R $, and the line $ x = x_2 $ intersects $ C $ at $ S $, such that the $ y $-coordinates of $ R $ and $ S $ are positive. Let $ \angle ROM = \frac{\pi}{6} $ and $ \angle SOM = \frac{\pi}{3} $, where $ O $ denotes the origin $ (0, 0) $. Let $ |XY| $ denote the length of the line segment $ XY $. Then which of the following statements is (are) TRUE?