Question:
The solution of x partial differential equation
\(\frac{\partial u}{\partial x}=2\frac{\partial u}{\partial t}+U\)
\(U(x,0)=6e^{-3x}\)
The solution of x partial differential equation
\(\frac{\partial u}{\partial x}=2\frac{\partial u}{\partial t}+U\)
\(U(x,0)=6e^{-3x}\)
\(\frac{\partial u}{\partial x}=2\frac{\partial u}{\partial t}+U\)
\(U(x,0)=6e^{-3x}\)
Updated On: Dec 19, 2024
- \(U=6e^{-3x-2t}\)
- \(U=6e^{3x-2t}\)
- \(U=6e^{3x+2t}\)
- \(U=6e^{-3x+2t}\)
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The Correct Option is A
Solution and Explanation
The correct option is(A): \(U=6e^{-3x-2t}\)
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