Question:
The solution of the differential equation
{x4+6x2+2(x+y)} dx-xdy=0
subject to the condition y(1)=0 is
The solution of the differential equation
{x4+6x2+2(x+y)} dx-xdy=0
subject to the condition y(1)=0 is
{x4+6x2+2(x+y)} dx-xdy=0
subject to the condition y(1)=0 is
Updated On: Mar 21, 2024
- 2y(x)=x2+x4(6log|x|-3)+4x
- y(x)=\(\frac{1}{2}\)[x2+x4(12log|x|+3)+4x]
- y(x)=x4+x2(12log|x|+3)-4x
- 2y(x)=x4+x2(12log|x|+3)-4x
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The Correct Option is D
Solution and Explanation
The correct answer is(D): 2y(x)=x4+x2(12log|x|+3)-4x
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