We are given the line \( 3x - y = -5 \), and we are asked to find the slopes of the lines that make an angle of 45° with this line.
Step 1: Find the slope of the given line
The slope of the given line \( 3x - y = -5 \) is:
\[
\text{slope} = \frac{3}{1} = 3
\]
Step 2: Use the formula for the angle between two lines
The formula for the angle between two lines with slopes \( m_1 \) and \( m_2 \) is:
\[
\tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|
\]
Since the angle is 45°, we have \( \tan 45^\circ = 1 \):
\[
1 = \left| \frac{3 - m}{1 + 3m} \right|
\]
Solve for \( m \):
\[
\frac{3 - m}{1 + 3m} = 1 \quad \Rightarrow \quad 3 - m = 1 + 3m
\]
\[
2 = 4m \quad \Rightarrow \quad m = \frac{1}{2}
\]
Similarly, for the other line making an angle of 45°, we solve:
\[
\frac{3 - m}{1 + 3m} = -1 \quad \Rightarrow \quad 3 - m = -(1 + 3m)
\]
\[
4 = 2m \quad \Rightarrow \quad m = -2
\]
Thus, the slopes are \( -2 \) and \( \frac{1}{2} \).
Thus, the correct answer is \( -2, \frac{1}{2} \).