Question:

The slope of the graph plotted between the square of the time period of a planet \( T^2 \) and the cube of its mean distance from the sun \( r^3 \) is:

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For planetary motion, Kepler's third law provides a direct relationship between the square of the time period and the cube of the mean distance.
Updated On: Mar 7, 2025
  • \( \frac{4\pi^2}{GM} \)
  • \( 4\pi GM \)
  • \( \frac{4\pi G}{M} \)
  • \( \frac{4\pi^2 M}{G} \)
  • Zero
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The Correct Option is A

Solution and Explanation

Step 1: Kepler’s third law states: \[ T^2 = \frac{4\pi^2 r^3}{GM} \] where: - \( T \) is the orbital period of the planet,
- \( r \) is the mean distance from the sun,
- \( G \) is the gravitational constant,
- \( M \) is the mass of the sun.
Step 2: The slope of the graph between \( T^2 \) and \( r^3 \) will be: \[ {slope} = \frac{4\pi^2}{GM} \] Step 3: This is the required slope, and it depends on the mass of the sun and the gravitational constant.
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