Question:

The shape and hybridisation in BF$_3$ is

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In molecules with three bonds and no lone pairs around the central atom (like BF\(_3\)), the hybridization is sp\(^2\) and the shape is trigonal planar.
Updated On: Apr 10, 2025
  • sp\(^2\), linear
  • sp\(^3\)d, planar
  • sp\(^2\), planar
  • sp\(^3\), planar
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The Correct Option is C

Solution and Explanation

Step 1: Understand the structure of BF\(_3\).
BF\(_3\) has three bonding pairs of electrons and no lone pairs on the central boron atom.
Since there are three bonding pairs and no lone pairs, the molecule adopts a trigonal planar geometry.
Step 2: Identify the hybridization.
In trigonal planar geometry, the central atom undergoes sp\(^2\) hybridization to form three sigma bonds with the fluorine atoms.
Step 3: Conclusion.
The shape of BF\(_3\) is planar, and the hybridization of the central atom is sp\(^2\).
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