Question:

The set of real values of x for which $ f(x) = \frac {x}{log\, x}$ increasing, is

Updated On: Feb 21, 2024
  • $\{x : x < e \}$
  • $\{ 1\}$
  • $\{x:x \geq e\}$
  • empty
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The Correct Option is C

Solution and Explanation

$f(x)= \frac{x}{\log x}$
$f'(x)=\frac{\log x \cdot 1-x \cdot \frac{1}{x}}{(\log x)^{2}}=\frac{(\log x-1)}{(\log x)^{2}}$
We know that, $f(x)$ is increasing (strictly) When $f^{\prime}(x)>0$
$\Rightarrow \frac{(\log x-1)}{(\log x)^{2}} >0 $
$\Rightarrow (\log x-1)>0$
$\Rightarrow \log x>1$
$\Rightarrow \log _{e} x>\log _{e} e$
$\Rightarrow x >e$
Hence, $x: x \geq e$
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Concepts Used:

Application of Derivatives

Various Applications of Derivatives-

Rate of Change of Quantities:

If some other quantity ‘y’ causes some change in a quantity of surely ‘x’, in view of the fact that an equation of the form y = f(x) gets consistently pleased, i.e, ‘y’ is a function of ‘x’ then the rate of change of ‘y’ related to ‘x’ is to be given by 

\(\frac{\triangle y}{\triangle x}=\frac{y_2-y_1}{x_2-x_1}\)

This is also known to be as the Average Rate of Change.

Increasing and Decreasing Function:

Consider y = f(x) be a differentiable function (whose derivative exists at all points in the domain) in an interval x = (a,b).

  • If for any two points x1 and x2 in the interval x such a manner that x1 < x2, there holds an inequality f(x1) ≤ f(x2); then the function f(x) is known as increasing in this interval.
  • Likewise, if for any two points x1 and x2 in the interval x such a manner that x1 < x2, there holds an inequality f(x1) ≥ f(x2); then the function f(x) is known as decreasing in this interval.
  • The functions are commonly known as strictly increasing or decreasing functions, given the inequalities are strict: f(x1) < f(x2) for strictly increasing and f(x1) > f(x2) for strictly decreasing.

Read More: Application of Derivatives