In 2010, the salaries of Ramesh, Ganesh, and Rajesh were in the ratio 6:5:7.
Let the common multiple be \( x \):
In 2015, the salary ratio was 3:4:3. Let the new common multiple be \( y \):
We are told that Ramesh’s salary increased by 25% from 2010 to 2015. That gives us:
\[ 6x \times 1.25 = 3y \Rightarrow 7.5x = 3y \Rightarrow y = \frac{7.5x}{3} = 2.5x \]
Now, Rajesh’s salary in:
Increase in Rajesh’s salary:
\[ 7.5x - 7x = 0.5x \]
Percentage increase:
\[ \frac{0.5x}{7x} \times 100 = \frac{50}{7} \approx 7.14\% \]
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: