Step 1: Identify the given resistor value clearly:
The given resistor value is \(4.7\,k\Omega \pm 5\%\).
Step 2: Resistor color-coding rules:
A resistor with four color bands is read as:
Step 3: Decode the given resistor value (4.7 kΩ):
\[ 4.7\,k\Omega = 4700\,\Omega \]
Expressed in standard form:
\[ 4700 = 47 \times 10^2 \]
Here:
Thus, the third band (multiplier) is Red.
Final Answer: Option (A) Red
1. Understand the Resistor Value:
The given resistance is \(R = 4.7 \, \text{k}\Omega \pm 5\%\). This can be written as \(R = 4.7 \times 10^3 \, \Omega \pm 5\%\). In standard form for a 4-band resistor, this is \(47 \times 10^2 \, \Omega \pm 5\%\).
2. Recall the Resistor Color Code Standard (4-Band):
3. Identify Digits, Multiplier, and Tolerance:
From the value \(47 \times 10^2 \, \Omega \pm 5\%\):
4. Determine the Color for Each Band using the Standard Code:
Color | Digit | Multiplier | Tolerance |
---|---|---|---|
Black | 0 | \(10^0 = 1\) | |
Brown | 1 | \(10^1\) | ±1% |
Red | 2 | \(10^2\) | ±2% |
Orange | 3 | \(10^3\) | |
Yellow | 4 | \(10^4\) | |
Green | 5 | \(10^5\) | ±0.5% |
Blue | 6 | \(10^6\) | ±0.25% |
Violet | 7 | \(10^7\) | ±0.1% |
Grey | 8 | \(10^8\) | ±0.05% |
White | 9 | \(10^9\) | |
Gold | \(10^{-1}\) | ±5% | |
Silver | \(10^{-2}\) | ±10% |
5. Answer the Question:
The question asks for the color of the third band, which represents the multiplier \(10^2\). The color corresponding to a multiplier of \(10^2\) is Red.
Answer: The colour of the third band is (A) red.