\(T_{\frac 12}=\frac {ln\ 2}{λ}\)
\(T_{\frac12} ln\ 2=λ\)
\(T_{\frac12}=\frac 1λ\)
\((λ+T_{\frac 12})=\frac {ln\ 2}{2}\)
The decay of atoms over time can be described using the formula \(N_t = N_0 . e^{(-λt)}\),
where
\(N_t\) represents the number of atoms at time \(t\)
\(N_0\) is the initial number of atoms,
\(λ\) is the decay constant.
For a specific case where \(t\) equals \(T_\frac12\):
\(2N_o = N_0 . e^{(-λ .T_\frac12)}\)
Simplifying this expression, we find:
\(2 = e^{(-λ . T_\frac 12)}\)
Taking the natural logarithm (ln) of both sides, we get:
\(ln\ (2) = -λ . T_\frac 12\)
Now, solving for \(T_\frac12\)
\(T_\frac 12 = \frac {ln\ (2)}{λ}\)
This equation establishes the relationship between the decay constant \((λ)\) and the half-life \((T_\frac 12)\).
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
Read More: Nuclei