The refractive index of glass is 1.6 and the speed of light in glass will be ……… . The speed of light in vacuum is \( 3.0 \times 10^8 \) ms\(^{-1}\).
Step 1: Understanding the Relationship Between Speed of Light and Refractive Index
The speed of light in a medium (\( v \)) is related to the refractive index (\( n \)) of the medium by: \[ v = \frac{c}{n} \] where:
- \( c = 3.0 \times 10^8 \) m/s (speed of light in vacuum),
- \( n = 1.6 \) (refractive index of glass).
Step 2: Substituting the Given Values
\[ v = \frac{3.0 \times 10^8}{1.6} \] \[ v = 1.875 \times 10^8 { m/s} \]
Step 3: Rounding Off the Answer
Approximating to three significant figures: \[ v \approx 1.88 \times 10^8 { m/s} \]
Step 4: Conclusion
Thus, the speed of light in glass is \( 1.88 \times 10^8 \) m/s.
Consider a refracting telescope whose objective has a focal length of 1m and the eyepiece a focal length of 1cm, then the magnifying power of this telescope will be ……..
For a thin prism, if the angle of the prism is \( A \) with a refractive index of 1.6, then the angle of minimum deviation will be …….
A ray coming from an object which is situated at zero distance in the air and falls on a spherical glass surface (\( n = 1.5 \)). Then the distance of the image will be ………. \( R \) is the radius of curvature of a spherical glass.}
For a plane mirror, the focal length is ……..
If the value of \( \cos \alpha \) is \( \frac{\sqrt{3}}{2} \), then \( A + A = I \), where \[ A = \begin{bmatrix} \sin\alpha & -\cos\alpha \\ \cos\alpha & \sin\alpha \end{bmatrix}. \]