The recoil velocity of a $ 4.0\, kg $ rifle that shoots a $ 0.050\, kg $ bullet at a speed of $ 280\text{ }m{{s}^{-1}} $ is:
- $ +3.5\text{ }m{{s}^{-1}} $
- $ -3.5\text{ }m{{s}^{-1}} $
- $ -\sqrt{(3.5)}\text{ }m{{s}^{-1}} $
- $ +\sqrt{(3.5)}\text{ }m{{s}^{-1}} $
The Correct Option is B
Solution and Explanation
Top Questions on momentum
- An object of mass \( m \) is projected from the origin in a vertical \( xy \)-plane at an angle \( 45^\circ \) with the x-axis with an initial velocity \( v_0 \). The magnitude and direction of the angular momentum of the object with respect to the origin, when it reaches the maximum height, will be:
Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Knowing the initial position \( x_0 \) and initial momentum \( p_0 \) is enough to determine the position and momentum at any time \( t \) for a simple harmonic motion with a given angular frequency \( \omega \).
Reason (R): The amplitude and phase can be expressed in terms of \( x_0 \) and \( p_0 \).
In the light of the above statements, choose the correct answer from the options given below:- A particle moves under the influence of a force in the XY-plane such that the components of its linear momentum $\vec{p}$ at any time $t$ are given by $p_x = p \sin t$ and $p_y = p \cos t$. The angle between $\vec{F}$ and $\vec{p}$ at that time is
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Which of the following graph shows the variation of velocity with mass for the constant momentum?
A body initially at rest undergoes rectilinear motion. The force-time (F-t) graph for the motion of the body is given below. Find the linear momentum gained by the body in 2 s.
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A ball is projected in still air. With respect to the ball the streamlines appear as shown in the figure. If speed of air passing through the region 1 and 2 are \( v_1 \) and \( v_2 \), respectively and the respective pressures, \( P_1 \) and \( P_2 \), respectively, then
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Concepts Used:
Momentum
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.