The given reaction is the reduction of acetic acid (CH₃COOH) to ethanol (CH₃CH₂OH).
Let's analyze each option:
The correct answer is (A) : LiAlH4 / ether.
The increasing order of acid strength of the following carboxylic acids is:
\[
(i) \text{(CH}_3\text{)}_3\text{C-COOH} \quad (ii) \text{(CH}_3\text{)}_2\text{CH-COOH} \quad (iii) \text{CH}_3\text{CH}_2\text{COOH}
\]