Question:
The reaction $Pb \left( NO _3\right)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration The dissolution of the precipitate is due to the formation of
The reaction $Pb \left( NO _3\right)_2$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration The dissolution of the precipitate is due to the formation of
Updated On: Jun 5, 2024
- $PbCl _2$
- $PbCl _4$
- $\left[ PbCl _4\right]^{2-}$
- $\left[ PbCl _6\right]^{2-}$
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The Correct Option is C
Solution and Explanation
When lead ions (Pb2+) react with chloride ions (Cl−), a white precipitate of lead(II) chloride (PbCl2) forms.
This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate (II) ion
So the correct answer option is (C)
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
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- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family