Question:
The reaction of \( {C}_6{H}_5 {CH=CHCH}_3 \) with HBr produces:
The reaction of \( {C}_6{H}_5 {CH=CHCH}_3 \) with HBr produces:
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In electrophilic addition reactions, the bromide ion attaches to the more substituted carbon atom in the intermediate carbocation.
Updated On: Mar 24, 2025
- \( {C}_6{H}_5{CH}_2{CH}_2{Br} \)
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The Correct Option is A
Solution and Explanation
The reaction of an alkene (in this case, styrene or \( {C}_6{H}_5{CH=CHCH}_3 \)) with HBr follows an electrophilic addition mechanism. In this reaction, the double bond of the alkene undergoes protonation to form a carbocation, which is then attacked by the bromide ion. The final product is the addition of Br to the more substituted carbon atom.
The reaction proceeds as:
\[
{C}_6{H}_5{CH=CHCH}_3 + {HBr} \rightarrow {C}_6{H}_5{CH}_2{CH}_2{Br}
\]
Thus, the correct product is \( {C}_6{H}_5{CH}_2{CH}_2{Br} \).
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