In an isothermal process, the pressure and volume follow Boyle's Law: \[ P V = \text{constant} \] whereas in an adiabatic process, the relation follows Poisson's equation: \[ P V^\gamma = \text{constant} \] For a given ratio of heat capacities \( \gamma = 1.5 \), using these relations, we can derive the pressure ratio as \( 2:1 \). Understanding these fundamental gas laws helps in solving thermodynamics problems efficiently.
Step 1: Understanding the Given Conditions - For an isothermal process, the pressure-volume relation is given by Boyle’s Law: \[ P V = \text{constant} \] Thus, if volume is doubled, the new pressure is: \[ P_2 = \frac{P_{\text{initial}}}{2} \] - For an adiabatic process, the pressure-volume relation is given by Poisson’s equation: \[ P V^\gamma = \text{constant} \] where \( \gamma \) is the adiabatic index, given as 1.5.
Step 2: Applying the Adiabatic Equation For an adiabatic process: \[ P_{\text{initial}} V^\gamma = P_1 (2V)^\gamma \] Rearranging: \[ P_1 = P_{\text{initial}} \times (2)^{-\gamma} \] Substituting \( \gamma = 1.5 \): \[ P_1 = P_{\text{initial}} \times (2)^{-1.5} = \frac{P_{\text{initial}}}{2^{1.5}} \] Since \( 2^{1.5} = \sqrt{8} = 2\sqrt{2} \), we get: \[ P_1 = \frac{P_{\text{initial}}}{2\sqrt{2}} \] \
Step 3: Equating \( P_1 \) and \( P_2 \) Given that \( P_1 = P_2 \), we equate the expressions: \[ \frac{P_{\text{initial}}}{2\sqrt{2}} = \frac{P_{\text{initial}}}{2} \] Solving for the pressure ratio: \[ \frac{P_{\text{initial}}}{P_{\text{initial (iso)}}} = \sqrt{2}:1 \] Thus, the correct ratio is: \[ \mathbf{\sqrt{2}:1} \]
The shaft of a 6 m wide gate in the figure will fail at a moment of 3924 kN.m about the hinge P. The maximum value of water depth \( h \) (in m) that the gate can hold is ......... (round off to the nearest integer).
Consider steady flow of water in the series pipe system shown below, with specified discharge. The diameters of Pipes A and B are 2 m and 1 m, respectively. The lengths of pipes A and B are 100 m and 200 m, respectively. Assume the Darcy-Weisbach friction coefficient, \( f \), as 0.01 for both the pipes.
The ratio of head loss in Pipe-B to the head loss in Pipe-A is ___________ (round off to the nearest integer).