In an isothermal process, the pressure and volume follow Boyle's Law: \[ P V = \text{constant} \] whereas in an adiabatic process, the relation follows Poisson's equation: \[ P V^\gamma = \text{constant} \] For a given ratio of heat capacities \( \gamma = 1.5 \), using these relations, we can derive the pressure ratio as \( 2:1 \). Understanding these fundamental gas laws helps in solving thermodynamics problems efficiently.
Step 1: Understanding the Given Conditions - For an isothermal process, the pressure-volume relation is given by Boyle’s Law: \[ P V = \text{constant} \] Thus, if volume is doubled, the new pressure is: \[ P_2 = \frac{P_{\text{initial}}}{2} \] - For an adiabatic process, the pressure-volume relation is given by Poisson’s equation: \[ P V^\gamma = \text{constant} \] where \( \gamma \) is the adiabatic index, given as 1.5.
Step 2: Applying the Adiabatic Equation For an adiabatic process: \[ P_{\text{initial}} V^\gamma = P_1 (2V)^\gamma \] Rearranging: \[ P_1 = P_{\text{initial}} \times (2)^{-\gamma} \] Substituting \( \gamma = 1.5 \): \[ P_1 = P_{\text{initial}} \times (2)^{-1.5} = \frac{P_{\text{initial}}}{2^{1.5}} \] Since \( 2^{1.5} = \sqrt{8} = 2\sqrt{2} \), we get: \[ P_1 = \frac{P_{\text{initial}}}{2\sqrt{2}} \] \
Step 3: Equating \( P_1 \) and \( P_2 \) Given that \( P_1 = P_2 \), we equate the expressions: \[ \frac{P_{\text{initial}}}{2\sqrt{2}} = \frac{P_{\text{initial}}}{2} \] Solving for the pressure ratio: \[ \frac{P_{\text{initial}}}{P_{\text{initial (iso)}}} = \sqrt{2}:1 \] Thus, the correct ratio is: \[ \mathbf{\sqrt{2}:1} \]
A bead of mass \( m \) slides without friction on the wall of a vertical circular hoop of radius \( R \) as shown in figure. The bead moves under the combined action of gravity and a massless spring \( k \) attached to the bottom of the hoop. The equilibrium length of the spring is \( R \). If the bead is released from the top of the hoop with (negligible) zero initial speed, the velocity of the bead, when the length of spring becomes \( R \), would be (spring constant is \( k \), \( g \) is acceleration due to gravity):
Which of the following statements are true?
A. The same Bernoulli's equation is applicable to all the points in the flow field if the flow is irrotational.
B. The value of "Constant in the Bernoulli's equation" is different for different streamlines if the flow is rotational.
C. When a nozzle is fitted at the end of a long pipeline, the discharge increases.
D. The velocity of flow at the nozzle end is more than that in the case of a pipe without a nozzle, the head in both cases being the same.
Choose the most appropriate answer from the options given below:
Observe the following data given in the table. (\(K_H\) = Henry's law constant)
Gas | CO₂ | Ar | HCHO | CH₄ |
---|---|---|---|---|
\(K_H\) (k bar at 298 K) | 1.67 | 40.3 | \(1.83 \times 10^{-5}\) | 0.413 |
The correct order of their solubility in water is
For a first order decomposition of a certain reaction, rate constant is given by the equation
\(\log k(s⁻¹) = 7.14 - \frac{1 \times 10^4 K}{T}\). The activation energy of the reaction (in kJ mol⁻¹) is (\(R = 8.3 J K⁻¹ mol⁻¹\))
Note: The provided value for R is 8.3. We will use the more precise value R=8.314 J K⁻¹ mol⁻¹ for accuracy, as is standard.