The ratio of the intensities of two waves is 16 : 9. The ratio of their amplitudes is
- 4:03
- 3:04
- I : 2
- 2 : l
The Correct Option is A
Solution and Explanation
$ \frac{I_1}{I_2} = \frac{a_1^2}{a_2^2} = \frac{16}{9}$
$\therefore \frac{a_1}{a_2} = \frac{4}{3}$
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- Given below are two statements, one labeled as Assertion (A) and the other as Reason (R).
Assertion (A): In Young’s double slit experiment, the fringes produced by red light are closer compared to those produced by blue light.
Reason (R): The fringe width is directly proportional to the wavelength of light.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
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Questions Asked in KEAM exam
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Then \( f'(-4) \) is equal to:- KEAM - 2024
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Let \( f(x) = \frac{x^2 + 40}{7x} \), \( x \neq 0 \), \( x \in [4,5] \). The value of \( c \) in \( [4,5] \) at which \( f'(c) = -\frac{1}{7} \) is equal to:
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The general solution of the differential equation \( \frac{dy}{dx} = xy - 2x - 2y + 4 \) is:
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\[ \int \frac{4x \cos \left( \sqrt{4x^2 + 7} \right)}{\sqrt{4x^2 + 7}} \, dx \]
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