Question:

The ratio of the escape velocity and the orbital velocity is

Updated On: Jul 7, 2022
  • $\sqrt2$
  • $\frac{1}{\sqrt2}$
  • 2
  • 44563
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The Correct Option is A

Solution and Explanation

Escape Velocity $=\sqrt{\frac{2 GM }{ r }}$, where $G$ is Gravitational constant, $M$ is the mass of the planet and $r$ is the radius of the orbit Orbital Velocity $=\sqrt{\frac{ GM }{ r }}$ Hence, the ratio of Escape velocity and Orbital velocity is $\sqrt{2}$.
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Concepts Used:

Escape Speed

Escape speed is the minimum speed, which is required by the object to escape from the gravitational influence of a plannet. Escape speed for Earth’s surface is 11,186 m/sec. 

The formula for escape speed is given below:

ve = (2GM / r)1/2 

where ,

ve = Escape Velocity 

G = Universal Gravitational Constant 

M = Mass of the body to be escaped from 

r = Distance from the centre of the mass