1. Solubility in Water:
AgCl $\rightleftharpoons$ Ag$^+$ + Cl$^-$ $K_{sp} = [Ag^+][Cl^-] = s^2$ where s is the solubility in mol/L.
Given $K_{sp} = 10^{-10}$ $s = \sqrt{10^{-10}} = 10^{-5}$ mol/L
2. Solubility in 0.1 M KCl Solution: In 0.1 M KCl solution, [Cl$^-$] = 0.1 M (due to common ion effect).
$K_{sp} = [Ag^+][Cl^-] = s'(0.1) = 10^{-10}$ where s' is solubility in 0.1 M KCl. $s' = \frac{10^{-10}}{0.1} = 10^{-9}$ mol/L
3. Calculate the Ratio:
Ratio $= \frac{Solubility in 0.1 M KCl}{Solubility in water} = \frac{10^{-9}}{10^{-5}} = 10^{-4}$
Solvent | Boiling Point (K) |
---|---|
Chloroform | 334.4 |
Diethyl Ether | 307.8 |
Benzene | 353.3 |
Carbon disulphide | 319.4 |
The output (Y) of the given logic gate is similar to the output of an/a :
A | B | Y |
0 | 0 | 1 |
0 | 1 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
List I (Spectral Lines of Hydrogen for transitions from) | List II (Wavelength (nm)) | ||
A. | n2 = 3 to n1 = 2 | I. | 410.2 |
B. | n2 = 4 to n1 = 2 | II. | 434.1 |
C. | n2 = 5 to n1 = 2 | III. | 656.3 |
D. | n2 = 6 to n1 = 2 | IV. | 486.1 |