The ratio of ages of A and B is 3:4. After 6 years, their ages will be in the ratio 4:5. What is A's current age?
36
- Step 1: Represent present ages - Let A's current age = $3x$ and B's current age = $4x$.
- Step 2: After 6 years - A's age = $3x + 6$, B's age = $4x + 6$.
- Step 3: Given ratio after 6 years - \[ \frac{3x + 6}{4x + 6} = \frac{4}{5} \]
- Step 4: Cross-multiply - \[ 5(3x + 6) = 4(4x + 6) \] \[ 15x + 30 = 16x + 24 \] \[ x = 6 \]
- Step 5: Find A's current age - $3x = 18$.
- Step 6: Conclusion - A's current age is 18 years, matching option (1).
Find the residue of \( (67 + 89 + 90 + 87) \pmod{11} \):
Match List-I with List-II and choose the correct option:
LIST-I (Infinite Series) | LIST-II (Nature of Series) |
---|---|
(A) \( 12 - 7 - 3 - 2 + 12 - 7 - 3 - 2 + \dots \) | (II) oscillatory |
(B) \( 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \dots \) | (IV) conditionally convergent |
(C) \( \sum_{n=0}^{\infty} \left( (n^3+1)^{1/3} - n \right) \) | (I) convergent |
(D) \( \sum_{n=1}^{\infty} \frac{1}{n \left( 1 + \frac{1}{n} \right)} \) | (III) divergent |
Choose the correct answer from the options given below:
Match List-I with List-II and choose the correct option:
LIST-I (Set) | LIST-II (Supremum/Infimum) |
---|---|
(A) \( S = \{2, 3, 5, 10\} \) | (III) Sup S = 10, Inf S = 2 |
(B) \( S = (1, 2] \cup [3, 8) \) | (IV) Sup S = 8, Inf S = 1 |
(C) \( S = \{2, 2^2, 2^3, \dots, 2^n, \dots\} \) | (II) Sup S = 5, Inf S = -5 |
(D) \( S = \{x \in \mathbb{Z} : x^2 \le 25\} \) | (I) Inf S = 2 |
Choose the correct answer from the options given below:
Which of the following are correct?
A. A set \( S = \{(x, y) \mid xy \leq 1 : x, y \in \mathbb{R}\} \) is a convex set.
B. A set \( S = \{(x, y) \mid x^2 + 4y^2 \leq 12 : x, y \in \mathbb{R}\} \) is a convex set.
C. A set \( S = \{(x, y) \mid y^2 - 4x \leq 0 : x, y \in \mathbb{R}\} \) is a convex set.
D. A set \( S = \{(x, y) \mid x^2 + 4y^2 \geq 12 : x, y \in \mathbb{R}\} \) is a convex set.
If p is a prime number and a group G is of the order p2, then G is:
When $10^{100}$ is divided by 7, the remainder is ?