The rate of diffusion of a gas A is √5 times more than of gas B. If the molar mass of A is x gmol-1, the molar mass of B ( in g mole-1) is
4x
5x
16x
25x
The correct option is: (B): 5x.
The rate of diffusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, this relationship is given by Graham's law of diffusion:
Rate A / Rate B = √(Molar mass B / Molar mass A)
Given that the rate of diffusion of gas A is √5 times more than that of gas B, we can write:
Rate A / Rate B = √5
Using Graham's law, we can set up the following equation:
√5 = √(Molar mass B / Molar mass A)
Squaring both sides of the equation to solve for the ratio of molar masses:
5 = Molar mass B / Molar mass A
Given that the molar mass of gas A is x g/mol, we can substitute this value into the equation:
5 = Molar mass B / x
Solving for the molar mass of gas B (Molar mass B):
Molar mass B = 5 * x
So, the molar mass of gas B is 5 times the molar mass of gas A, which is consistent with the provided answer of 5x g/mol.
The matter is made up of very tiny particles and these particles are so small that we cannot see them with naked eyes.
The three states of matter are as follows: