The total order of a reaction is the sum of the exponents in the rate law. In this case, the rate law is: \[ {rate} = [A]^1 [B]^{3/2} \] The order with respect to \(A\) is 1, and the order with respect to \(B\) is \( \frac{3}{2} \).
Therefore, the total order is: \[ 1 + \frac{3}{2} = 2.5 \]
Observe the following reactions:
\( AB(g) + 25 H_2O(l) \rightarrow AB(H_2S{O_4}) \quad \Delta H = x \, {kJ/mol}^{-1} \)
\( AB(g) + 50 H_2O(l) \rightarrow AB(H_2SO_4) \quad \Delta H = y \, {kJ/mol}^{-1} \)
The enthalpy of dilution, \( \Delta H_{dil} \) in kJ/mol\(^{-1}\), is:
Kc for the reaction \[ A(g) \rightleftharpoons T(K) + B(g) \] is 39.0. In a closed one-litre flask, one mole of \( A(g) \) was heated to \( T(K) \). What are the concentrations of \( A(g) \) and \( B(g) \) (in mol L\(^{-1}\)) respectively at equilibrium?