Question:

The range of the function $ f(x)\frac{{{x}^{2}}-x+1}{{{x}^{2}}+x+1} $ where $ x\in R, $ is

Updated On: Jun 7, 2024
  • $ (-\infty ,3] $
  • $ (-\infty ,\,\infty ) $
  • $ [3,\infty ) $
  • $ \left[ \frac{1}{3},3 \right] $
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The Correct Option is D

Solution and Explanation

Let $ y=\frac{{{x}^{2}}-x+1}{{{x}^{2}}+x+1} $ $ \Rightarrow $ $ {{x}^{2}}(y-1)+4(y+1)+(y-1)=0 $ Now, $ D\ge 0 $ $ \Rightarrow $ $ {{(y+1)}^{2}}-4{{(y-1)}^{2}}\ge 0 $ $ \Rightarrow $ $ -3{{y}^{2}}-3+10y\ge 0 $ $ \Rightarrow $ $ 3{{y}^{2}}-10y+3\le 0 $ $ \Rightarrow $ $ y=\frac{10\pm \sqrt{64}}{6}\le 0 $ $ \left( y-\frac{1}{3} \right)(y-3)\le 0 $ $ \Rightarrow $ $ y\in \left[ \frac{1}{3},3 \right] $
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions