Question

The radius of the path of a charged particle of mass \( m \) and charge \( q \) moving with a speed \( v \) in a magnetic field \( B \) is given by:

• A. \( \frac{mv^2}{qB} \)
• B. \( \frac{mv}{qB} \)
• C. \( \frac{2m\pi v}{qB} \)
• D. \( \frac{mv}{B^2} \)

Hint:

The radius of the path of a charged particle in a magnetic field is directly proportional to the velocity and inversely proportional to the charge and magnetic field strength.

Answer 1

The Correct Option is B

The radius of the path followed by a charged particle moving in a magnetic field is given by the formula: \[ r = \frac{mv}{qB} \] Where:
- \( m \) is the mass of the particle,
- \( v \) is its velocity,
- \( q \) is its charge,
- \( B \) is the magnetic field strength.
Thus, the correct answer is \( \frac{mv}{qB} \).