Question:
The radius of the innermost electron orbit of a hydrogen atom is \(5.3×10^{–11} m\). What are the radii of the n=2 and n=3 orbits?
The radius of the innermost electron orbit of a hydrogen atom is \(5.3×10^{–11} m\). What are the radii of the n=2 and n=3 orbits?
Updated On: Sep 30, 2023
Hide Solution
Verified By Collegedunia
Solution and Explanation
The radius of the innermost orbit of a hydrogen atom, \(r_1=5.3×10^{-11}m.\)
Let \(r_2\) be the radius of the orbit at n=2. It is related to the radius of the innermost orbit as:
\(r_2=(n)^2r_1\)
\(=4×5.3×10^{-11}=2.12×10^{-10}m\)
For n=3,we can write the corresponding electron radius as:
\(r_3=(n)^2r_1\)
\(=9×5.3×10^{-11}=4.77×10^{-10}m\)
Hence, the radii of an electron for n=2 and n=3 orbits are \(2.12×10^{-10}m\) and \(4.77×10^{-10}m\) respectively.
Let \(r_2\) be the radius of the orbit at n=2. It is related to the radius of the innermost orbit as:
\(r_2=(n)^2r_1\)
\(=4×5.3×10^{-11}=2.12×10^{-10}m\)
For n=3,we can write the corresponding electron radius as:
\(r_3=(n)^2r_1\)
\(=9×5.3×10^{-11}=4.77×10^{-10}m\)
Hence, the radii of an electron for n=2 and n=3 orbits are \(2.12×10^{-10}m\) and \(4.77×10^{-10}m\) respectively.
Was this answer helpful?
0
0
Top Questions on Atoms
- Assertion (A): The potential energy of an electron revolving in any stationary orbit in a hydrogen atom is positive.
Reason (R): The total energy of a charged particle is always positive. - Prove that, in the Bohr model of the hydrogen atom, the time period of revolution of an electron in the \( n \)-th orbit is proportional to \( n^3 \).
- An atom is subjected to a weak uniform magnetic field \( B \). The number of lines in its Zeeman spectrum for the transition from \( n = 2, l = 1 \) to \( n = 1, l = 0 \) is
- ........ is a potent vasodilator.
- Which one of the following corresponds to the wavelength of line spectrum of H atom in its Balmer series? (R = Rydberg constant)
View More Questions