Question:
The radius of Na atom forming bcc lattice (in Å)?
The radius of Na atom forming bcc lattice (in Å)?
Updated On: Dec 18, 2023
Hide Solution
Verified By Collegedunia
Solution and Explanation
The radius of Na atom forming bcc lattice (in Å) is 113.
Was this answer helpful?
0
0
Top Questions on The solid state
- How many kinds of Bravais lattice are possible in a crystal?
- Bihar Board XII - 2025
- Chemistry
- The solid state
- The percentage of free space in a body-centred cubic unit cell is
- Bihar Board XII - 2025
- Chemistry
- The solid state
- The number of atoms present in body-centred cubic unit cell is
- Bihar Board XII - 2025
- Chemistry
- The solid state
- Which of the following is not a crystalline solid?
- Bihar Board XII - 2025
- Chemistry
- The solid state
- A metal crystallizes in simple cubic lattice. The volume of one unit cell is \( 6.4 \times 10^{-7} \, \text{pm}^3 \). What is the radius of the metal atom in pm?
- AP EAPCET - 2025
- Chemistry
- The solid state
View More Questions
Questions Asked in JEE Main exam
Match List - I with List - II.
- JEE Main - 2025
- Thermodynamics
- The variance of the numbers 8, 21, 34, 47, \dots, 320, is:
- JEE Main - 2025
- Arithmetic Progression and Variance
- The value of \( (\sin 70^\circ)(\cot 10^\circ \cot 70^\circ - 1) \) is:
- JEE Main - 2025
- Trigonometric Identities
- Let A and B be the two points of intersection of the line \( y + 5 = 0 \) and the mirror image of the parabola \( y^2 = 4x \) with respect to the line \( x + y + 4 = 0 \). If \( d \) denotes the distance between A and B, and \( a \) denotes the area of \( \Delta SAB \), where \( S \) is the focus of the parabola \( y^2 = 4x \), then the value of \( (a + d) \) is:
- JEE Main - 2025
- Angle between a Line and a Plane
- The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 nm light is:
- JEE Main - 2025
- wave interference
View More Questions