The radius of gyration of a body about an axis at a distance of $6\, cm$ from its centre of mass is $10\, cm$. Then, its radius of gyration about a parallel axis through its centre of mass will be
$T_{A B}=I_{ CM }+M h^{2}$
$M K_{AB}^{2}=M K_{ CM }^{2}+M h^{2}$
$K_{A B}^{2}=K_{ CM }^{2}+h^{2}$
Given, $K_{A B}=10\, cm,\, h=6\, cm$
Putting them, we get
$K_{ CM }=8\, cm$
Was this answer helpful?
0
0
Top Questions on System of Particles & Rotational Motion
The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.