The radius of a circular track is 200 m. Find the angle of banking of the track, if the maximum speed at which a car can be driven safely along it is 25 m/s.
The angle of banking \( \theta \) for a car moving along a curved track without relying on friction is given by the formula:
\[ \tan(\theta) = \frac{v^2}{r g} \] where \( v = 25 \, {m/s} \) is the speed of the car, \( r = 200 \, {m} \) is the radius of the track, and \( g = 9.8 \, {m/s}^2 \) is the acceleration due to gravity. Substituting the values:
\[ \tan(\theta) = \frac{25^2}{200 \times 9.8} = \frac{625}{1960} = 0.318 \] \[ \theta = \tan^{-1}(0.318) = 17.7^\circ \]
A sportsman runs around a circular track of radius $ r $ such that he traverses the path ABAB. The distance travelled and displacement, respectively, are:
A body of mass $100 \;g$ is moving in a circular path of radius $2\; m$ on a vertical plane as shown in the figure. The velocity of the body at point A is $10 m/s.$ The ratio of its kinetic energies at point B and C is: (Take acceleration due to gravity as $10 m/s^2$)
Predict the type of cubic lattice of a solid element having edge length of 400 pm and density of 6.25 g/ml.
(Atomic mass of element = 60)
Staying in comfort at home gives one more happiness than travelling.