The radius of a circular track is 200 m. Find the angle of banking of the track, if the maximum speed at which a car can be driven safely along it is 25 m/s.
The angle of banking \( \theta \) for a car moving along a curved track without relying on friction is given by the formula:
\[ \tan(\theta) = \frac{v^2}{r g} \] where \( v = 25 \, {m/s} \) is the speed of the car, \( r = 200 \, {m} \) is the radius of the track, and \( g = 9.8 \, {m/s}^2 \) is the acceleration due to gravity. Substituting the values:
\[ \tan(\theta) = \frac{25^2}{200 \times 9.8} = \frac{625}{1960} = 0.318 \] \[ \theta = \tan^{-1}(0.318) = 17.7^\circ \]
A body of mass $100 \;g$ is moving in a circular path of radius $2\; m$ on a vertical plane as shown in the figure. The velocity of the body at point A is $10 m/s.$ The ratio of its kinetic energies at point B and C is: (Take acceleration due to gravity as $10 m/s^2$)
If a body is performing uniform circular motion with velocity \( v \) and radius \( R \), then identify the true statements from the following:
A. Its velocity \( v \) is constant.
B. Acceleration is always directed towards the centre and its magnitude is \( a = \frac{v^2}{R} \).
C. Angular momentum is constant in magnitude but its direction keeps changing.
D. Angular velocity of the body \( = \frac{v}{R} \).
Choose the most appropriate answer from the options given below.
The slope of the tangent to the curve \( x = \sin\theta \) and \( y = \cos 2\theta \) at \( \theta = \frac{\pi}{6} \) is ___________.
Solve the following L.P.P. by graphical method:
Maximize:
\[ z = 10x + 25y. \] Subject to: \[ 0 \leq x \leq 3, \quad 0 \leq y \leq 3, \quad x + y \leq 5. \]