We have been given an expression of displacement in terms of time. Thus, differentiating this equation with respect to time once will give us an expression for velocity, and differentiating once again with respect to time will give us an expression for acceleration.
Hence,
\(V = 3t^2 - 8t + 16\) – (A)
\(A = 6t - 8\) – (B)
While we have obtained the expressions for velocity and acceleration, we cannot determine their absolute values at a particular time simply from the given statement 1.
Now, we go to Statement II
we have:
\(20 = 3t ^ 2 - 8t + 16\) after solving the equation we get,
\(t=4+2( \sqrt 7)\)
When we put the value of t in (B), we get value of acceleration.
The correct option is (C)