The quadratic equation, whose roots are \( \frac{4 + \sqrt{7}}{2} \) and \( \frac{4 - \sqrt{7}}{2} \), is:
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For a quadratic equation with known roots \( r_1 \) and \( r_2 \), use the relations:
\text{Sum of roots} = -\frac{\text{coefficient of } x}{\text{leading coefficient}}, \quad \text{Product of roots} = \frac{\text{constant term}}{\text{leading coefficient}}.
We are given the roots of the quadratic equation as \( \frac{4 + \sqrt{7}}{2} \) and \( \frac{4 - \sqrt{7}}{2} \). The sum of the roots is:
\[
\text{Sum of roots} = \frac{4 + \sqrt{7}}{2} + \frac{4 - \sqrt{7}}{2} = 4
\]
The product of the roots is:
\[
\text{Product of roots} = \left( \frac{4 + \sqrt{7}}{2} \right) \times \left( \frac{4 - \sqrt{7}}{2} \right) = \frac{16 - 7}{4} = \frac{9}{4}
\]
The quadratic equation is given by:
\[
x^2 - (\text{Sum of roots})x + \text{Product of roots} = 0
\]
Substituting the sum and product of the roots:
\[
x^2 - 4x + \frac{9}{4} = 0
\]
Multiplying through by 4 to clear the fraction:
\[
4x^2 - 16x + 9 = 0
\]
Thus, the correct answer is \( 4x^2 - 16x + 9 = 0 \).