Question

The product ‘Q’ of the following reactions is:

• A.

  

• B.

  

• C.

  

• D.

  

Hint:

Friedel-Crafts acylation adds a carbonyl group, which can be reduced by Clemmensen reduction to form alkylbenzenes.

Answer 1

The Correct Option is B

This is a two-step reaction: 1. Friedel-Crafts acylation: \[ \text{C}_6\text{H}_6 + \text{CH}_3\text{CH}_2\text{COCl} \xrightarrow{\text{AlCl}_3} \text{C}_6\text{H}_5\text{COCH}_2\text{CH}_3 \] Phenylpropanone (aromatic ketone) is formed. 2. Clemmensen reduction: \[ \text{C}_6\text{H}_5\text{COCH}_2\text{CH}_3 \xrightarrow{\text{Zn-Hg/HCl}} \text{C}_6\text{H}_5\text{CH}_2\text{CH}_2\text{CH}_3 \] The carbonyl group is reduced to -CH\(_2\)-, giving n-propylbenzene.
Hence, the final product is: \[ \boxed{\text{C}_6\text{H}_5\text{CH}_2\text{CH}_2\text{CH}_3} \]