The product P in the reaction, 




Grignard Reaction with Nitriles: Ketone Formation
This transformation involves the nucleophilic addition of a Grignard reagent to a nitrile group, followed by acidic hydrolysis to yield a ketone.
R-C≡N + CH3MgBr → R-C(-N=MgBr)(CH3)
R-C(-N=MgBr)(CH3) + H3O+ → R-CO-CH3 + NH4+ + MgBrOH
Final Product: The reaction converts the nitrile (R-C≡N) to a methyl ketone (R-CO-CH3)
Therefore, the correct answer is D (a ketone with structure R-CO-CH3).
Think of the nitrile as a "carbon delivery system":
1. The Nitrile Group
The -C≡N group is linear and highly polarized, with partial positive charge on carbon. This makes it:
2. The Grignard Reagent
CH3MgBr provides:
Starting with 3-methoxybenzonitrile:
3-Methoxybenzonitrile
+ CH3MgBr →
3-Methoxyacetophenone
The methoxy group (-OCH3) remains untouched because:
Key Takeaway: Grignard + nitrile → ketone, every time.
Therefore, the correct product is D (3-methoxyacetophenone).
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80