For any parallelogram, the diagonals bisect each other.
The midpoint of \((–4, 3)\) and \((–1, –4)\) will also lie on \(7y + 3x + c = 0\).
The midpoint of \((–4, 3)\) and \((–1, –4)\) is \(\bigg(\frac{-4-1}{2}, \frac{3+(-4)}{2}\bigg)\) = \((-2.5, -0.5)\).
On substituting in the equation, we get \(7(-0.5) +3(-2.5) +c = 0\)
\(c = 11\)
Hence, option D is the correct answer.