\(The\ planes: 2x-y+4z=5 \ and \ 5x-2.5y+10z=6\ are\)
passes through \((0,0,\frac 54)\)
The equations of the planes are
\(2x - y + 4z = 5\) \(.....(1)\)
\(5x - 2.5y + 10z = 6\) \(.....(2)\)
It can be seen that,
\(\frac {a_1}{a_2} =\frac {2}{5}\)
\(\frac {b_1}{b_2}=\frac {-1}{-2.5}=\frac {2}{5 }\)
\(\frac {c_1}{c_2} =\frac {4}{10} = \frac {2}{5}\)
\(∴\frac {a_1}{a_2}=\frac {b_1}{b_2}=\frac {c_1}{c_2}\)
Therefore, the given planes are parallel.
Hence, the correct answer is B.
Show that the following lines intersect. Also, find their point of intersection:
Line 1: \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} \]
Line 2: \[ \frac{x - 4}{5} = \frac{y - 1}{2} = z \]
Information Table
| Information | Amount (₹) |
|---|---|
| Preference Share Capital | 8,00,000 |
| Equity Share Capital | 12,00,000 |
| General Reserve | 2,00,000 |
| Balance in Statement of Profit and Loss | 6,00,000 |
| 15% Debentures | 4,00,000 |
| 12% Loan | 4,00,000 |
| Revenue from Operations | 72,00,000 |