Step 1: Define shrinkage factor.
Shrinkage factor = \(\frac{\text{Shrunk length}}{\text{Original length}}\).
Step 2: Substitution.
Original length = 10 cm, Shrunk length = 9.5 cm.
\[
\text{Shrinkage Factor} = \frac{9.5}{10} = 0.95
\]
Step 3: Conclusion.
Therefore, the shrinkage factor is 0.95. Correct answer is (C).
Match List-I with List-II
| List-I | List-II |
|---|---|
| (A) Alidade | (III) Plain table surveying |
| (B) Arrow | (I) Chain surveying |
| (C) Bubble Tube | (II) Leveling |
| (D) Stadia hair | (IV) Theodolite surveying |
Choose the correct answer from the options given below:
Match List-I with List-II
| List-I | List-II |
|---|---|
| Type of correction | Formula used |
| (The symbols have their usual meaning) | |
| (A) Sag correction | (I) \( \pm L(1 - h/R) \) |
| (B) Pull correction | (II) \( -\frac{1}{24} \times \left(\frac{W}{P}\right)^2 \) |
| (C) Temperature correction | (III) \( \pm (T_f - T_s)L \) |
| (D) Mean sea level correction | (IV) \( \pm \frac{(P_l - P_s) \times L}{AE} \) |
Choose the correct answer from the options given below: