Step 1: Define shrinkage factor.
Shrinkage factor = \(\frac{\text{Shrunk length}}{\text{Original length}}\).
Step 2: Substitution.
Original length = 10 cm, Shrunk length = 9.5 cm.
\[
\text{Shrinkage Factor} = \frac{9.5}{10} = 0.95
\]
Step 3: Conclusion.
Therefore, the shrinkage factor is 0.95. Correct answer is (C).
Reciprocal levelling is performed for points P and Q by placing the same levelling instrument at A and B. The observations of staff readings are tabulated as below. 
If the Reduced Level (RL) of P is 115.246 m, then the true RL of Q, in m, is _______ (rounded off to 3 decimal places)