The energy of a photon is given by:
\( E = \frac{hc}{\lambda} \) where
\( h \) is Planck's constant,
\( c \) is the speed of light, and
\( \lambda \) is the wavelength.
For photoemission to occur, the energy of the photon must be greater than or equal to the work function \( W_0 \).
For \( \lambda = 700 \text{nm} \), the photon energy is lower than the work function, meaning no photoemission occurs.
Given below are two statements: one is labelled as Assertion (A) and the other one is labelled as Reason (R).
Assertion (A): Emission of electrons in the photoelectric effect can be suppressed by applying a sufficiently negative electron potential to the photoemissive substance.
Reason (R): A negative electric potential, which stops the emission of electrons from the surface of a photoemissive substance, varies linearly with the frequency of incident radiation.
In light of the above statements, choose the most appropriate answer from the options given below: