Nucleotides are joined together by:
For the AC circuit shown in the figure, $ R = 100 \, \text{k}\Omega $ and $ C = 100 \, \text{pF} $, and the phase difference between $ V_{\text{in}} $ and $ (V_B - V_A) $ is 90°. The input signal frequency is $ 10^x $ rad/sec, where $ x $ is:
Two parabolas have the same focus $(4, 3)$ and their directrices are the $x$-axis and the $y$-axis, respectively. If these parabolas intersect at the points $A$ and $B$, then $(AB)^2$ is equal to:
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?

Nucleic acids are explained as long-chain polymeric molecules, where the monomer (the repeating unit) is referred to as the nucleotides. Thus many times nucleic acids are referred to as polynucleotides. The two main kinds of nucleic acids are-
Chemically, DNA is a composition of a pentose sugar, phosphoric acid, and some cyclic bases that have nitrogen in them. DNA has β-D-2-deoxyribose in it, in the form of the sugar moiety.
The RNA molecule is a composition of phosphoric acid, a pentose sugar, and some cyclic bases containing nitrogen. The sugar moiety inside RNA molecules is β-D-ribose.