Question:

The pair of electron in the given carbanion, $CH_3C \equiv$ $C^{-}$, is present in which of the following orbitals ?

Updated On: Apr 20, 2025

$sp^3$
$sp^2$
$sp$
$2 p$

Hide Solution

Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Carbanion and Hybridization

The given carbanion, $CH_3C \equiv C^{-}$, has a negative charge on the carbon that is part of the triple bond (C≡C). The carbon atoms involved in the triple bond (≡) typically undergo sp hybridization to form the bonding orbitals. In this case:

sp Hybridization: The carbon with the negative charge (C⁻) is sp-hybridized because of the triple bond. In sp hybridization, one s orbital and one p orbital mix to form two sp hybrid orbitals.
Lone Pair: The electron pair that gives the carbanion's negative charge is present in one of these sp hybrid orbitals, where it is not involved in the bonding of the triple bond but resides as a lone pair on the negatively charged carbon.
Lone Pair Location: Thus, the lone pair in the carbanion $CH_3C \equiv C^{-}$ is located in an sp hybrid orbital.

Conclusion:

The lone pair of electrons in the carbanion $CH_3C \equiv C^{-}$ resides in an sp hybrid orbital due to the nature of the triple bond and sp hybridization of the carbon atoms involved.

Was this answer helpful?

List - I (Complex)	List - II (Hybridisation)
(A) \([\text{CoF}_6]^{3-}\)	(I) \( d^2 sp^3 \)
(B) \([\text{NiCl}_4]^{2-}\)	(II) \( sp^3 \)
(C) \([\text{Co(NH}_3)_6]^{3+}\)	(III) \( sp^3 d^2 \)
(D) \([\text{Ni(CN}_4]^{2-}\)	(IV) \( dsp^2 \)

Questions Asked in NEET exam

Match List I with List II:

List I		List II
A	EFibrous joints	I	Adjacent vertebrae, limited movement
B	Cartilaginous joints	II	Humerus and Pectoral girdle, rotational movement
C	Hinge joints	III	Skull, don’t allow any movement
D	Ball and socket joints	IV	Knee, help in locomotion

Choose the correct answer from the options given below:

NEET (UG) - 2024
Joints

View Solution

List I	List II
A	Pterophyllum	I	Hag fish
B	Myxine	II	Saw fish
C	Pristis	III	Angel fish
D	Exocoetus	IV	Flying fish

List I	List II
A	Axoneme	I	Centriole
B	Cartwheel pattern	II	Cilia and flagella
C	Crista	III	Chromosome
D	Satellite	IV	Mitochondria

View More Questions

Concepts Used:

Hybridisation

Hybridization refers to the concept of combining atomic orbitals in order to form new hybrid orbitals that are appropriate to represent their bonding properties. Hybridization influences the bond length and bond strength in organic compounds.

Types of Hybridization:

sp Hybridization

sp hybridization is observed while one s and one p orbital inside the identical principal shell of an atom mix to shape two new equal orbitals. The new orbitals formed are referred to as sp hybridized orbitals.

sp² Hybridization

sp² hybridization is observed whilst ones and p orbitals of the same shell of an atom blend to shape three equivalent orbitals. The new orbitals formed are referred to as sp² hybrid orbitals.

sp³ Hybridization

When one ‘s’ orbital and 3 ‘p’ orbitals belonging to the identical shell of an atom blend together to shape 4 new equal orbitals, the sort of hybridization is referred to as a tetrahedral hybridization or sp³.

sp³d Hybridization

sp³d hybridization involves the joining of 3p orbitals and 1d orbital to form 5 sp³d hybridized orbitals of identical energy. They possess trigonal bipyramidal geometry.

sp³d² Hybridization

With 1 s three p’s and two d’s, there is a formation of 6 new and identical sp³d² orbitals.