Question

The output of the given circuit diagram is

• A. \[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 1 & 1 \\ \hline \end{array}\]
• B. \[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 1 & 0 \\ \hline \end{array}\]
• C. \[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 1 & 0 \\ \hline \end{array}\]
• D. \[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 1 & 0 \\ \hline \end{array}\]

Answer 1

The Correct Option is C

The circuit diagram consists of logic gates. By analyzing each gate’s behavior step-by-step and evaluating the output \( Y \) for each input combination of \( A \) and \( B \), we can determine the output for each case. After constructing the truth table for the circuit, we find that the correct output matches option (3).

Thus, the answer is:

\[ \begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ 1 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 1 & 1 \\ \hline \end{array} \]