Question:

The order of differential equation of all circles of given radius $'a'$ is _____

Updated On: Apr 14, 2024
  • 4
  • 2
  • 1
  • 3
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The Correct Option is B

Solution and Explanation

Let the centre of circle be $( h , k )$ and radius $a$, then its equation will be
$(x-h)^{2}+(y-k)^{2}=a^{2}$
Since, there are two parameters $h$ and $k .$ So, the differential equation is of order 2
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Concepts Used:

Order and Degree of Differential Equation

The equation that helps us to identify the type and complexity of the differential equation is the order and degree of a differential equation.

The Order of a Differential Equation:

The highest order of the derivative that appears in the differential equation is the order of a differential equation.

The Degree of a Differential Equation:

The highest power of the highest order derivative that appears in a differential equation is the degree of a differential equation. Its degree is always a positive integer.

For examples:

  • 7(d4y/dx4)3 + 5(d2y/dx2)4+ 9(dy/dx)8 + 11 = 0 (Degree - 3)
  • (dy/dx)2 + (dy/dx) - Cos3x = 0 (Degree - 2)
  • (d2y/dx2) + x(dy/dx)3 = 0 (Degree - 1)