To find the degree of a differential equation, first make sure all derivatives are polynomial, and eliminate any fractional powers or roots. The degree is determined by the highest power of the highest-order derivative in the equation.
The correct answer is: (B): 6.
We are tasked with determining the degree of the differential equation:
\(1 + \left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^2 = \sqrt[3]{\frac{d^2y}{dx^2} + 1}\)
Step 1: Express the equation in terms of derivatives
To find the degree, we need to ensure that the equation is polynomial in the derivatives of \( y \). Start by clearing the cube root by raising both sides of the equation to the power of 3:
\( \left( 1 + \left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^2 \right)^3 = \frac{d^2y}{dx^2} + 1 \)
Step 2: Eliminate the cube root and simplify
By simplifying both sides of the equation, we can rewrite the equation in a form where the derivatives are only raised to integer powers. This step essentially removes the fractional powers and simplifies the equation to a polynomial in \( \frac{dy}{dx} \) and \( \frac{d^2y}{dx^2} \). The left side of the equation becomes a polynomial, while the right side has only the second derivative of \( y \), ensuring that we have a polynomial equation in terms of the derivatives.
Step 3: Identify the degree of the equation
The degree of a differential equation is defined as the highest power of the highest order derivative in the equation. In this case, after simplifying the equation, the highest order derivative is \( \frac{d^2y}{dx^2} \), and the highest power of this derivative is 6, making the degree of the equation 6.
Conclusion:
The degree of the differential equation is (B): 6.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is