The odds that A agrees with the truth are 3 : 2 and the odds that B agrees with the truth are 5 : 3. In what percent of cases are they likely to agree with each other on an identical point?
Show Hint
Always express probabilities in fractions before converting them into percentages to minimize calculation errors.
We define the probabilities of A and B agreeing with the truth:
The probability that A agrees with the truth:
\[
P(A) = \frac{3}{3+2} = \frac{3}{5}
\]
The probability that B agrees with the truth:
\[
P(B) = \frac{5}{5+3} = \frac{5}{8}
\]
The probabilities of A and B disagreeing:
\[
P(A') = 1 - \frac{3}{5} = \frac{2}{5}
\]
\[
P(B') = 1 - \frac{5}{8} = \frac{3}{8}
\]
Now, the probability that A and B agree:
\[
P(A \cap B) + P(A' \cap B') = \left( \frac{3}{5} \times \frac{5}{8} \right) + \left( \frac{2}{5} \times \frac{3}{8} \right)
\]
\[
= \left( \frac{15}{40} \right) + \left( \frac{6}{40} \right) = \frac{21}{40}
\]
\[
\frac{21}{40} \times 100 = 52.5%
\]
Since 52.5% is not in the options, the correct answer is None of these.